won10 ie图标:别都不理我呀....帮我解答一下这道数学题吧~~~

先用代数式表示出虚根，有公式的，可惜我忘了，是什么+i什么的，表示出来以后再根据 “ 两虚根的立方均为实数 ”这个条件最后得出结论。

方程有一对共轭虚根。求根公式：{-b±[根号下-(b方-4ac)]×i}.所以两个跟为：：[-b±2(p-q)的绝对值]/2，…………
好难打，自己再捉摸看看

x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 x^2+2(p+q)x+2(p^2+q^2)=0 ??????????????????????????

忘记了,呵呵,不好意思哦,1年没读书了,如果是上海的话可以加QQ聊聊天 224293