钱璇古装图片:初一数学

来源:百度文库 编辑:高校问答 时间:2024/05/05 09:31:20
[(x^2-2xy+y^2)+(3x-3y)+2]/(x-y+1)

[(x^2-2xy+y^2)+(3x-3y)+2]/(x-y+1)
= [(x-y)^2+3(x-y)+2]/(x-y+1) 分子利用十字相乘
= [(x-y+1)(x-y+2)]/(x-y+1)
= x-y+2