易码平台怎么充值:数学计算

来源:百度文库 编辑:高校问答 时间:2024/04/29 11:05:31
x-y/2x+1 *(2x+1/x+y - 2xy+y/y^2-x^2)+y/x+Y

x-y/2x+1 *(2x+1/x+y - 2xy+y/y^2-x^2)+y/x+Y
解:原式=x-y/2x+1*[-x (2x+1)]/(y-x)(y+x)+y/y+x
=x/y+x+y/y+x
=y+x/y+x
=1