英雄无敌3部队经验系统:数学计算题

来源:百度文库 编辑:高校问答 时间:2024/05/12 14:41:07
(1-1/(2^2))*(1-1/(3^2))*(1-1/(4^2))…(1-1/(99^2))*(1-1/(100^2))

=(1-1/2)(1+1/2)...(1-1/100)(1+1/100)
=(1/2)(3/2)(2/3)(4/3)..(99/100)(101/100)
=101/200

平方差公式
=(1-1/2)(1+1/2)...(1-1/100)(1+1/100)
=(1/2)(3/2)(2/3)(4/3)..(99/100)(101/100)
=101/200