君乐宝开菲尔酸奶价格:物理电磁学问题

来源:百度文库 编辑:高校问答 时间:2024/04/25 06:36:54
A single square loop of wire 23 cm on a side is placed with its face parallel to the magnetic field between the pole pieces of a large magnet. When 6.04 A flows in the coil, the torque on it is 0.306 m*N. What is the magnetic field strength?

F=BIL M=FL
代如数据得0.153=BIL*0.02875m
0.153=B6.04A*0.0575m*0.02875m
B= 6.04A*0.0575m*0.02875m / 0.153 m*N
B= 0.65147 高斯

the magnetic torque N=uxB(cross product of magnetic moment and field),and the magnetic moment of the loop u=I.A,where A is the area of the loop.hence,B=N/(I.A)

I am poor in English.