芦之湖:初三数学

来源:百度文库 编辑:高校问答 时间:2024/04/30 14:31:20
若b^m=6,b^n=5,则b^(4m+2n)=
请写一下计算过程

b^(4m+2n)
=b^4m*b^2n
=b^m^4*b^n^2
=6^4*5^2
=1296*25
=32400

b^(4m+2n)=(b^4m)*(b^2n)=((b^m)^4)*((b^n)^2)=6^4*5^2=32400

b^(4m+2n)=(b^4m)*(b^2n)=((b^m)^4)*((b^n)^2)=6^4*5^2=32400

b^(4m+2n)=(b^4m)*(b^2n)=((b^m)^4)*((b^n)^2)=6^4*5^2=32400