合肥人眼中的中科大:1/(2/3)/(3/4)/(4/5)/(5/6)/(6/7)/(7/8)
来源:百度文库 编辑:高校问答 时间:2024/04/29 20:11:43
等于多少?要列算式哦!而且是用简便方法计算!
快来
快来
1/(2/3)/(3/4)/(4/5)/(5/6)/(6/7)/(7/8)
=1*3/2*4/3*5/4*6/5*7/6*8/7
=1*8/2
=4
(列成分数更明显)
先找规律
1/(2/3)=1*(3/2)=(1*3)/2
1/(2/3)/(3/4)=1*(3/2)*(4/3)=(1*3*4)/(2*3)
依此进行
...
1/(2/3)/(3/4)/(4/5)/(5/6)/(6/7)/(7/8)=(1*3*4*5*6*7*8)/(2*3*4*5*6*7)=4
飘过~~
/x-1/+/x-2/+/x-3/+......+/x-617/
1/2,1/3,2/3,6/3,( ),18/3
3/2,2/3,3/4,1/3,3/8,( )
1/1+1/2+1/3+1/4+。。。。+1/N 是多少
1/2,3/2,1/5,-1/8,-2/13,(?)
3/2=2+1/1*2=1/1+1/2
1/2+1/3+1/4+1/5+。。。。。1/50=???
1/1*2+1/2*3+1/3*4+...+1/2000*2001
1/(1*2)+1/(2*3)+1/(3*4)+..+1/(99*100)
// 4,3,2,0,1,-3,( ) // 1/2,1/6,1/3,2,( ),3,1/2