lua获取文件修改时间:(xy+1)(x+1)(y+1)+xy
来源:百度文库 编辑:高校问答 时间:2024/05/06 15:14:58
(xy+1)(x+1)(y+1)+xy因式分解
(xy+1)(x+1)(y+1)+xy
=(xy+1)(xy+x+y+1)+xy
=(xy+1)[(xy+1)+x+y]+xy
=(xy+1)^2+x(xy+1)+y(xy+1)+xy
=(xy+1+x)(xy+1+y)
(xy+1)(x+1)(y+1)+xy
=(xy+1)(xy+x+y+1)+xy
=(xy+1)[(xy+1)+x+y]+xy
=(xy+1)^2+x(xy+1)+y(xy+1)+xy
=(xy+1+x)(xy+1+y)