马鞍山师专黄玉叶:tan67°30'-tan22°30'=?
来源:百度文库 编辑:高校问答 时间:2024/06/05 10:21:53
不用计算机,简便的!过程!
解:tan67°30'-tan22°30'
=tan67°30'-cot67°30'
=(sin^267°30'-cos^267°30')/(sin67°30'cos67°30')
=-cos135°/sin135°
=-1
cot22°30'-tan22°30'
=2/sin45°
=2根号2