kz321哈萨克网xalhar:y= sin2x + acon2x 知道对称轴是 x=x/8 a=
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y= sin2x + acon2x =sqr(1+a^2)sin(2x+θ)…………(tanθ=a)
它的对称轴方程为2x+θ=kπ+π/2即x=kπ/2+π/4-θ/2=π/8(k为整数)
解得θ=kπ+π/4
又因0<=θ<π
故θ=π/4
a=1
y= sin2x + acon2x =sqr(1+a^2)sin(2x+θ)…………(tanθ=a)
它的对称轴方程为2x+θ=kπ+π/2即x=kπ/2+π/4-θ/2=π/8(k为整数)
解得θ=kπ+π/4
又因0<=θ<π
故θ=π/4
a=1