龙皇武神更新时间:tan(π/4+α)-tan(π/4-α)=2tan2α

tan π/4 = 已知α,β≠Kπ/2 且tanα-tanβ=2tanαtanαtanβ tan(π/4+α)-tan(π/4-α)=2tan2α 求证:tan(π/4+α)-tan(π/4-α)=2tan2α (1)已知tan(π/4+α)=2,求tanα,sin2α+sin^2α+cos2α tan(π/4+θ)+tan(π/4-θ)=4,cos2θ=? 已知α,β≠Kπ/2 且tanα-tanβ=2tanαtanαtanβ 求证sin（2α＋β）/sinβ=3 3已知α+β=π／4，则（tanα+1）（tanβ+1）= 已知0<α<π/2,tanα/2+1/(tanα/2)=5/2,求sin(α-π/3) 已知α是锐角,且tan（π/4+α)=2,求tanα和（sin2α·cosα-sinα)/(sin2α·cos2α）的值