高校问答笔记本风扇接口定义:一道小学应用题(简便算法)
来源：百度文库 编辑：高校问答 时间：2024/04/29 12:52:41
5/12*4/15+2/9=1/9+2/9=1/3
11/12-1/5*5/6+5/4=11/12-1/6+5/4=3/4+5/4=2
(17/12-5/6)*1/7=7/12*1/7=1/12
（1）7-5/12*4/15+2/9
=7-1/9+2/9
=7+1/9
=7又1/9
（2）11/12-1/5*5/6+5/4
=11/12-1/6+5/4
=11/12-2/12+15/12
=9/12+15/12
=24/12
=2
（3）（17/12-5/6）*1/7
=（17/12-10/12）*1/7
=7/12*1/7
=1/12
7-5/12×4/15+2/9
=7-5×4/15×12+2/9
=7-1/9+2/9
=7+1/9
=7又1/9
11/12-1/5× 5/6+5/4
=11/12-1/6+5/4
=11-2+15/12
=24/12
=2
（17/12-5/6 ）1/7
=17-10/12 ×1/7
=7/12×1/7
=1/12
7-5/12×4/15+2/9
=7-20/180+2/9
=7-1/9+2/9
=7-1/9
11/12-1/5×5/6+4/5
=11/12-2/12+4/5
=9/12+4/5
=31/20
(17/12-5/6)×1/7
=7/12*1/7
=1/12
（1）7-5/12*4/15+2/9
=7-1/9+2/9
=7+1/9
=7又1/9
（2）11/12-1/5*5/6+5/4
=11/12-1/6+5/4
=11/12-2/12+15/12
=9/12+15/12
=24/12
=2
（3）（17/12-5/6）*1/7
=（17/12-10/12）*1/7
=7/12*1/7
=1/12
(1)
7-5/12*4/15+2/9
=7-1/9+2/9
=7+1/9
=7又1/9
(2)
11/12-1/5× 5/6+5/4
=11/12-1/6+5/4
=11-2+15/12
=24/12
=2
(3)
（17/12-5/6 ）1/7
=17-10/12 ×1/7
=7/12×1/7
=1/12