民间借贷没有转账凭证:谁会解这道题：(X-5)/(X-7)+(X-2)/(X-4)=(X-3)/(X-5)+(X-4)/(X-6)求X的值

来源：百度文库 编辑：高校问答 时间：2024/05/06 04:00:44
要过程
不会啊,我要解题过程,WHO能帮帮我
是除,不是乘,大哥

1+2/(x-7)+1+2/(x-4)=1+2/(x-5)+1+2/(x-6)
1/(x-7)+1/(x-4)=1/(x-5)+1/(x-6)
x平方-13x+28=x平方-11x+30
x=1

通分吧

化简

通分化简

谁会解这道题：(X-5)/(X-7)+(X-2)/(X-4)=(X-3)/(X-5)+(X-4)/(X-6)求X的值 谁会解:x-3/5x=y-6 谁会解虚数x? 谁会解虚数x? 5x-2/(x+2)(x-2)-(x-1)(x+2)/(x+2)(x-2)=0 问几道题目：1.(2*x*x*x+x*x-11x-5)/(x+2)的余式是 . 计算[(x-1)/(x-2)-(x-2)(x-3)-(x-3)/(x-4)+(x-4)(x-5)]/(2x-7) x*(x/3)=(x-5)*(x/3+1)/2 x=? (x-4)(x-2)-(x-1)(x+3),其中x=-2/5 (x*x*x-x*x+x)/(x*x*x+1)+(x*x+x+1)/[(1-x*x)/x)]