高校问答用跳蛋刺激女朋友:一道物理题，谢谢！！！
来源：百度文库 编辑：高校问答 时间：2024/05/01 01:10:10
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|______|·|______|
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|________________|
一端封闭的玻璃管内有一定量的气体，管内水面高于管外水面，现把玻璃管缓慢竖直向上提起，则管
内气体体积______,管内外水平面高度差_______.
怎样分析???
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|````````|·|````````|
|_____|·|_____|
|···|·|···|
|···|·|···|
|·······|
|____________|
```````| |
```````|__|
|``````|·|``````|
|______|·|______|
|···|·|···|
|···|·|···|
|········|
|________________|
一端封闭的玻璃管内有一定量的气体，管内水面高于管外水面，现把玻璃管缓慢竖直向上提起，则管
内气体体积______,管内外水平面高度差_______.
怎样分析???
`
``````````⌒
`````````|```|
`````````|__|
|````````|·|````````|
|_____|·|_____|
|···|·|···|
|···|·|···|
|·······|
|____________|
一端封闭的玻璃管内有一定量的气体，管内水面高于管外水面，现把玻璃管缓慢竖直向上提起，则管
内气体体积 变大 ,管内外水平面高度差 变大.
此体可以用假设的方法.假设体积变大,所以管内压强减小,而外界大气压不变,故高度差也要增大.同理假设体积变小和不变的情况,都会产生矛盾.所以,管
内气体体积 变大 ,管内外水平面高度差 变大.
传说中的守护神,呵呵又见面了,还记得我吗?