|pf1|+|pf2|=2a(定义)=2|f1f2|=4c所以a=2c,b=(根号3)*c设椭圆方程x^2/(4*c^2)+y^2/(3*c^2)=1代入p(2,根号3)得c^2=1a^2=4,b^2=3所以方程为x^2/4+b^2/3=1