五年级回顾拓展四反思:设等比数列{an}的公比为q前n项和Sn>0,n∈N*

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(1)求q的取值范围(2)设bn=an+2 -3/2 an+1试比较Sn和Tn的大小 要详细解答谢谢
an+2是象An+2,不是an再加上2(下同)

q>0
b1=a3-3/2a2
Tn=Sn-a1-a2-3/2(Sn-a1)
=-1/2Sn+1/2a1-a2
n=1 S1=a1>0 q>0 an>0
T1=-a2<S1
T2=-1/2a1-1/2a2+1/2a1-a2=-3/2a2<s2
....
Tn<0
Tn<Sn

q>0
b1=a3-3/2a2
Tn=Sn-a1-a2-3/2(Sn-a1)
=-1/2Sn+1/2a1-a2
n=1 S1=a1>0 q>0 an>0
T1=-a2<S1
T2=-1/2a1-1/2a2+1/2a1-a2=-3/2a2<s2
....
Tn<0
Tn<Sn

q>0
b1=a3-3/2a2
Tn=Sn-a1-a2-3/2(Sn-a1)
=-1/2Sn+1/2a1-a2
n=1 S1=a1>0 q>0 an>0
T1=-a2<S1
T2=-1/2a1-1/2a2+1/2a1-a2=-3/2a2<s2
....
Tn<0
Tn<Sn