腐蚀牌匾制作:初一数学题
来源:百度文库 编辑:高校问答 时间:2024/05/06 10:38:58
1.计算:(0.04)^2003×{(-5)^2003}^2
2.计算:2(x^3)^2×x^3-(3x^3)^3+5x^2×x^7
2.计算:2(x^3)^2×x^3-(3x^3)^3+5x^2×x^7
1.(0.04)^2003×{(-5)^2003}^2
= (0.04)^2003×[(-5)^2]^2003
=(0.04×25)^2003
=1^2003=1
2. 2(x^3)^2×x^3-(3x^3)^3+5x^2×x^7
=2x^9-9x^9+5x^9
=-2x^9
1) (0.04)^2003×{(-5)^2003}^2
=(1/25)^2003 ×25^2003
=1
2) 2(x^3)^2×x^3-(3x^3)^3+5x^2×x^7
=2x^9-3x^9+5x^9
=4x^9
(0.04)^2003×{(-5)^2003}^2 =1^2003=1
2(x^3)^2×x^3-(3x^3)^3+5x^2×x^7=-2x^9
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yun