重生之贱受终成渣79:急!!!数学高手请!

来源:百度文库 编辑:高校问答 时间:2024/05/14 05:58:08
化简x^3-x^2y+xy^2-y^3/x-y
注明过程!!!!!!!!!!!!!!!!!!!!!!!!

解:(x^3-x^2y+xy^2-y^3)/(x-y)
=[x^2(x-y)+y^2(x-y)]/(x-y)
=(x-y)(x^2+y^2)/(x-y)
=x^2+y^2

x^3-x^2y+xy^2-y^3/x-y=x^2+y^2