天府通余额查询为0:大哥大姐帮个忙一道挺难的C题

#include <graphics.h>
#include <math.h>
#include <conio.h>
#define PI 3.14159
#define T PI/180
#define NN 36
#define DT PI/NN
#define DIST 0.8
#define R 190
static int n=1;
void trans(t,s)
float t[3];
float s[3][3];
{
s[0][0]=cos(t[1])*cos(t[2]); s[0][1]=cos(t[1])*sin(t[2]);
s[0][2]=-sin(t[1]);
s[1][0]=sin(t[0])*sin(t[1])*cos(t[2])-cos(t[0])*sin(t[2]);
s[1][1]=sin(t[0])*sin(t[1])*sin(t[2])+cos(t[0])*cos(t[2]);
s[1][2]=sin(t[0])*cos(t[1]);
s[2][0]=cos(t[0])*sin(t[1])*cos(t[2])+sin(t[0])*sin(t[2]);
s[2][1]=cos(t[0])*sin(t[0])*sin(t[2])-sin(t[0])*cos(t[2]);
s[2][2]=cos(t[0])*cos(t[1]);
}
void draw(m,da,db)
float m[3][3],da,db;
{
float f[3],f0 , x0,y0,x1,y1,x2,y2;
f[0]=R*sin(da)*cos(db); f[1]=R*sin(da)*sin(db);
f[2]=R*cos(da);
f0=f[0]*m[0][2]+f[1]*m[1][2]+f[2]*m[2][2];
if(f0<=0) n=1;
else
{
x0=300.0;y0=165.0;
x2=(m[0][0]*f[0]+m[1][0]*f[1]+m[2][0]*f[2])+x0;
y2=(m[0][1]*f[0]+m[1][1]*f[1]+m[2][1]*f[2])*DIST+y0;
if(n==1) {n=2;x1=x2;y1=y2;}
else
{
line(x1,y1,x2,y2);
x1=x2;y1=y2;
}
}
}

main()
{
float d[3],r[3][3],ta,tb;
char k;
int gdriver=VGA,gmode=VGAMED, i,p=1;
initgraph(&gdriver,&gmode,"c:\\tc");
setbkcolor(BLACK);setcolor(GREEN);
d[1]=30*T; d[2]=10*T;
do{
for(i=0;i<=361;i+=1)
{
k=kbhit();
if(k!=0)break;
setactivepage(p);
d[0]=i*T;
cleardevice();
trans(d,r);
for(tb=0.0;tb<PI;tb+=DT)
{
n=1;
for(ta=0.0;ta<2.1*PI;ta+=DT) draw(r,ta,tb);}
for(ta=0.0;ta<PI;ta+=DT)
{
n=1;
for(tb=0.0;tb<2.1*PI;tb+=DT) draw(r,ta,tb);
}
setvisualpage(p);delay(150);p=1-p;
}
}

while(k==0);
getch();closegraph();
}