倔强乐队谱:分式方程,我不会做,大家帮个忙啊!

来源:百度文库 编辑:高校问答 时间:2024/05/04 15:03:18
1/(x-10)+1/(x-6)=1/(x-7)=1/(x-9)

1/(x-10)+1/(x-6)=1/(x-7)=1/(x-9)
3/[(x-10)(x-7)]=3/[(x-6)(x-9)]
(x-10)(x-7)=(x-6)(x-9)
(x-10)/(x-6)=(x-9)/(x-7)
[(x-8)-2]/[(x-8)+2]=[(x-8)-1]/[(x-8)+1]
……

估计朝错了

1/(x-7)=1/(x-9)
是这样吗